本⽂实例讲述了C++求逆序对的⽅法,分享给⼤家供⼤家参考之⽤。具体实现⽅法如下:
#include int array[] = {3, 9, 7, 4, 5, 2}; const int size = sizeof array / sizeof *array;int temp[size]; //int numbers[size]; int reversePair(int *numbers, int start, int last, int &index, int &count){ if(start == last) return 0; int mid = (last - start) / 2 + start; reversePair(numbers, start, mid, index, count); reversePair(numbers, mid + 1, last, index, count); for(int i = start; i <= last; i++) temp[i] = numbers[i]; int index1 = start, index2 = mid + 1; index = start; while(index1 <= mid && index2 <= last) { if(temp[index1] > temp[index2]) { numbers[index] = temp[index2]; count += mid - index1 + 1; index++; index2++; } else if(temp[index1] == temp[index2]) { numbers[index] = temp[index1]; index++; index1++; index2++; } else if(temp[index1] < temp[index2]) { numbers[index] = temp[index1]; index++; index1++; } } if(index1 <= mid) { while(index1 <= mid) { numbers[index] = temp[index1]; index++; index1++; } } else { while(index2 <= last) { numbers[index] = temp[index2]; index++; index2++; } } return count;} void main(){ int count = 0; int index = 0; reversePair(array, 0, size - 1, index, count); cout << \"count = \" << count << endl;} 希望本⽂所述对⼤家C++算法设计的学习有所帮助。 因篇幅问题不能全部显示,请点此查看更多更全内容